3[x+3]=16+2x

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Solution for 3[x+3]=16+2x equation:


Simplifying
3[x + 3] = 16 + 2x

Reorder the terms:
3[3 + x] = 16 + 2x
[3 * 3 + x * 3] = 16 + 2x
[9 + 3x] = 16 + 2x

Solving
9 + 3x = 16 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
9 + 3x + -2x = 16 + 2x + -2x

Combine like terms: 3x + -2x = 1x
9 + 1x = 16 + 2x + -2x

Combine like terms: 2x + -2x = 0
9 + 1x = 16 + 0
9 + 1x = 16

Add '-9' to each side of the equation.
9 + -9 + 1x = 16 + -9

Combine like terms: 9 + -9 = 0
0 + 1x = 16 + -9
1x = 16 + -9

Combine like terms: 16 + -9 = 7
1x = 7

Divide each side by '1'.
x = 7

Simplifying
x = 7

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